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Questions not related to the fuel type, like Manual Gearbox, Body Work, Lights, Interior trim and Seats, Steering, Brakes, Beeping, Wheels and Tyres to be asked in this topic only.
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I want to put a button near the central lock button (maybe left of radio) . I want to make the tailgate open when I press this button. For this, if I make the connection shape as in the attached picture, will the system work.
Does + 12V DC voltage to pin 2 of 40V GR break the BSI?
When entering a car park where LPG is prohibited when the doors are locked, baggage control is carried out to see if there is LPG.
I have to open the driver's door so that the attendant can open the tailgate. whereas I want the tailgate to be opened without opening the driver's door.
Assuming that the unlock 'motor' is indeed a solenoid which what I would expect, have you given any thought to the operating time?
Already mentioned earlier but what was the reason for not adding a second boot release switch alongside the existing one? As said, let the BSI do the working out.
If you do go with the added switch on the motor feed I would want to add a circuit to give a similar power 'pulse' to the BSI. I'm not saying getting it wrong will damage the solenoid but when it comes to door locking I wouldn't leave the timing to the length of your button press. What if the button gets stuck or something else presses against it?
If at first you don't succeed, destroy all the evidence and pretend you never tried
You are correct, holding the "new " button for too long may burn out the coil. However I do not have the specifications of this solenoid. Some solenoids have two stage activation using a pull-in and hold-in coils allowing them to be powerful but still run continuously. Some can run continuously like the coils in some relays.
In the circuit diagram there is an integral switch in the lock mechanism to tell the BSI that the door is open. This is passed to the central display to tell the driver the door is open, it's also used by the BSI to cut the power to the solenoid when the door is open. How long does the BSI provide power to the solenoid if the door doesn't open? I don't know. I would guess only a few seconds.
I don't think just pressing the button until you hear the lock clunk will cause any harm (under normal circumstances). Yes, if something pushes on the switch inadvertently, there might be a problem.
If you are worried about the solenoid burning out, you could use the relay circuit, above, and hook up a de-latch circuit to the switch wire in the lock and/or hook up a timer. However that's beginning to become complicated. Do-able but complicated. You could "guard" or hide the button or whatever. It's up to the user.
You can get very small self-contained timer circuits from Ebay that should be able to do this job but again that's up to the user.
I think Simuzer wanted to unlock the boot irrespective of the status of the rest of the locks (locked, unlocked, dead locked). If you put the new switch in parallel with the door unlock button, when the doors are locked, the button wont work. The BSI will ignore unlock requests from the button. So he would need to unlock the doors (if they were locked) before he could "pop" the boot for the attendant. For some reason he might not want to do that.
